AIIMS2018Physics-Friction

AIIMS 2018 Physics Kinetic and Static Friction MCQ Question

Type: MCQ-conceptual-Medium-Class 11

A body of mass 2 kg is placed on a horizontal surface having kinetic friction 0.4 and static friction 0.5. If the force applied on

A

8 N

B

10 N

C

20 N

D

2.5 N

Correct Answer

Option D

Detailed Explanation

To determine the maximum static friction force, we use the formula fs=μsNf_s = \mu_s \cdot N, where μs=0.5\mu_s = 0.5 and N=mg=2kg×9.8m/s2=19.6NN = mg = 2 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 19.6 \, \text{N}. Thus, fs=0.5×19.6N=9.8Nf_s = 0.5 \times 19.6 \, \text{N} = 9.8 \, \text{N}. Since option D (2.5 N) is less than the maximum static friction, the body will not move. Options A (8 N), B (10 N), and C (20 N) exceed the static friction limit, causing the body to slide, which is why they are incorrect.

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