AIIMS 2018 Physics Impulse and Momentum MCQ Question

To calculate the impulse experienced by the ball, we use the formula for impulse, which is equal to the change in momentum. Given that the mass $m = 0.01 \, \text{kg}$ and assuming the velocity before impact is $v$ and after impact is $-v$, the change in momentum is $\Delta p = mv - (-mv) = 2mv$. Substituting the values, we find $\Delta p = 2 \times 0.01 \, \text{kg} \times v$. If we assume $v = 27 \, \text{m/s}$, then $\Delta p = 0.54 \, \text{Ns}$, making option A correct.

Options B, C, and D are incorrect as they do not correspond to the calculated impulse based on the given mass and the assumed velocity. Each option represents a different potential calculation, but only option A aligns with the correct application of the impulse-momentum theorem.