AIIMS2019Chemistry-Organic Chemistry

AIIMS 2019 Chemistry Reactions of Alkenes MCQ Question

Type: MCQ-conceptual-Medium-Class 11

In the reaction sequence

CH2=CH2Hypochlorous acidXYCH2OHCH2OH\text{CH}_2 = \text{CH}_2 \xrightarrow{\text{Hypochlorous acid}} \text{X} \xrightarrow{\text{Y}} \begin{array}{c} \text{CH}_2\text{OH} \\ | \\ \text{CH}_2\text{OH} \end{array}

X\text{X} and Y\text{Y} respectively are:

A

O CH2CH2\begin{array}{c} \text{O} \\ \diagup \ \diagdown \\ \text{CH}_2-\text{CH}_2 \end{array} and heat

B

CH3CH2Cl\text{CH}_3\text{CH}_2\text{Cl} and NaOH\text{NaOH}

C

CH3CH2OH\text{CH}_3\text{CH}_2\text{OH} and H2SO4\text{H}_2\text{SO}_4

D

CH2ClCH2OH\text{CH}_2\text{ClCH}_2\text{OH} and NaHCO3\text{NaHCO}_3

Correct Answer

Option D

Detailed Explanation

The reaction sequence begins with the addition of HOCl to ethylene (H₂C=CH₂), yielding a chlorohydrin (H₂C(OH)−CH₂(Cl)). The subsequent treatment with sodium bicarbonate (NaHCO₃) facilitates the dehydrochlorination and oxidation of the intermediate, resulting in the formation of ethylene glycol (CH₂OH−CH₂OH), which is compound Y. Other options are not applicable as they do not correspond to the products formed in the given reaction pathway. Understanding the transformation from alkenes to alcohols through halohydrin formation and subsequent reactions is crucial in organic chemistry.

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