AIIMS Chemistry Organic Chemistry – Some Basic Principles & Techniques Class 11 Questions

The complete reaction is shown below.

IUPAC name of

The complete reaction is shown below.

$\text{A} \xrightarrow{\text{Ph}-\text{SO}_2\text{Cl}} \text{B} \xrightarrow{\text{KOH}} \text{C} \xrightarrow{\text{C}_2\text{H}_5\text{I}} \text{D}$'C' is water solubleCorrect structure of A and D are

Correct order of SN2 reaction is:

Stability order of following carbocation is :

Find the end product of reaction

$\text{Ph}-\text{CH}_2-\text{CH}=\text{CH}-\text{CH}_3 \xrightarrow[\text{(ii) Alk. KOH}]{\text{(i) Br}_2}$

Assertion: Phenol is more acidic then m-methoxy phenol Reason: $\text{–OCH}_3$ shows +I effect

Compare stability of free radicals

(I) $\text{CH}_3-\dot{\text{C}}\text{H}-\text{CH}_3$

(II) $\text{C}_6\text{H}_5-\dot{\text{C}}\text{H}_2$

(III)$\dot{\text{C}}\text{H}_2-\text{CH}(\text{CH}_3)_2 \qquad \text{(IV) }\dot{\text{C}}\text{H}_2-\text{CH}_3$

$\text{Phenol} + \text{Aniline} \xrightarrow{\text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^- / \text{KOH}} \text{Major Product: Product will be :}$

Write IUPAC name of following compound

$-\text{NH}-\text{C}(=\text{O})-\text{NH}-\text{NH}_2\text{ group}\rangle \xrightarrow{\text{(i)HCl} / \text{(ii)}\Delta} \text{Major product of following reaction}$

Identify structure of ‘P’ and ‘Q’ Correct order of pKa value is:

$\langle\text{1-chloro-2-methoxybenzene structure}\rangle \xrightarrow{\text{HNO}_3 / \text{H}_2\text{SO}_4} \text{Major Product, product will be :}$

Correct order of basic strength is:

Which of the following statement is correct for oleum ?

IUPAC name of give compound:

Assertion: Anhydrides are more reactive than ester for nucleophilic substitution.

Reason:– $\text{R.COO}^{-}$ is better leaving group than $\text{R-O}^{-}$

Suitable reagent for following conversion

The complete reaction is shown below.

Assertion: m-Bromotoluene can be prepared by m-toluidene.

Reason: Amino group is meta directing

The complete reaction is shown below.

The complete reaction is shown below.

If HBr attacks on left side double bond of the conjugated diene, then the formation of tertiary carbocation occur which is highly stable and if HBr attacks on right side double bond, the formation of secondary carbocation occurs which is less stable.

The complete reaction is shown below.

$\text{CH}_3-\text{C}\equiv\text{CH} \xrightarrow{\quad2\text{HBr}\quad} \longrightarrow \xrightarrow{\quad\text{H}_2\text{O}\quad} \text{Product , Product is:}$

Which of the following has highest ratio of reducing hydrogen / OH :

$\text{H}_2\text{O}_2$ is obtained by which of the following:

The chemical reaction is shown below:

Assertion : The name of the hydrocarbon $(\text{CH}_3)_2\text{CHCH}_2\text{CH}_2\text{CH}(\text{CH}_3)\text{CH}_2\text{CH}_3$ is 2,5-dimethylheptane and not 3,6-dimethylheptane.

Reason : Numbering should be done in such a way that the sum of the locants on the parent chain is the biggest possible number.

Assertion: $\text{ZrI}_4$ is useful in purification of Zirconium (Zr)

Reason: $\text{ZrI}_4$ sublimes at room temperature.

In the reaction sequence

$\text{CH}_2 = \text{CH}_2 \xrightarrow{\text{Hypochlorous acid}} \text{X} \xrightarrow{\text{Y}} \begin{array}{c} \text{CH}_2\text{OH} \\ | \\ \text{CH}_2\text{OH} \end{array}$

$\text{X}$ and $\text{Y}$ respectively are:

MnO is:

Assertion: Pure $\text{N}_2$ is obtained from $\text{Ba}(\text{N}_3)_2$ but not from $(\text{NH}_4)_2\text{Cr}_2\text{O}_7$

Reason: On decomposition $(\text{NH}_4)_2\text{Cr}_2\text{O}_7$ gives $\text{O}_2$ gas.

Which have melting point below 500 C °

Yellow color of chlorine water fades because of:

ortho-Nitophenol is less soluble in water than p- and m-nitrophenols because:

In the following structure, the double bonds are marked I, II, III and IV

Assertion : Out of $\text{CrO}_3$ & $\text{Al}_2\text{O}_3$, $\text{CrO}_3$ having lower melting point than $\text{Al}_2\text{O}_3$. Reason : Oxidation state of $\text{Cr}$ in $\text{CrO}_3$ is high

Assertion : 1-Butene has less dipole moment than 1-butyne. Reason : 1-Butyne has more s-character.

For the diazonium ions the order of reactivity towards the diazo-coupling with phenol in the presence of dilute $\text{NaOH}$ is:

Acetanilide on nitration followed by alkaline hydrolysis mainly gives-

Assertion : Toluene reacts with $\text{Cl}_2/\text{FeCl}_3$, to give $p$-isomer as the major product. Reason : This is due to steric hindrance at the $o$-position, so it always from $p$-isomer as the major product.

Assertion : Oxidation state of $\text{Cr}$ in $\text{CrO}_5$, is $+10$ by conventional method is wrong.

Reason : Because the maximum oxidation state of $\text{Cr}$ can not be more than $+6$ since it has 5 electron in $3\text{d}$ orbital and one electron in $4\text{s}$ orbital.

The following compound is used as:

Assertion: Hydrogen peroxide forms two series of salts called peroxides and hydroperoxides.

Reason: Hydrogen peroxide molecule has two replaceable hydrogen atoms.

The compound most reactive towards $\text{S}_\text{N}1$ reaction is:

Which of the following intermediate is not expected to be formed in the following reaction? [Reaction Image: (Iodomethyl)cyclohexane $\xrightarrow{\text{H}_2\text{O}}$ 1-methylcyclohexanol]

Assertion : $\text{KCl}$ when treated with concentrated $\text{H}_2\text{SO}_4$ produces $\text{HCl}$. Reason : Concentrated $\text{H}_2\text{SO}_4$ is reducing agent.

Assertion : $\langle\text{1-chloro-1-methylcyclobutane Structure}\rangle$ is less reactive than $\langle\text{chlorocyclobutane Structure}\rangle$ towards nucleophilic substitution reactions ($\text{S}_\text{N}1$).

Reason : Alkyl halides which can form less stable carbocation favour $\text{S}_\text{N}1$ reaction.