The reactions A and B are given with same temperature and same concentration but rate of reaction A is double than B. If pre-exponential factor is same for both reactions then difference in activation energy $E_A - E_B$ is?
A
$-RT \ln 2$
B
$RT \ln 2$
C
$2RT$
D
$\frac{RT}{2}$

Question

The reactions A and B are given with same temperature and same concentration but rate of reaction A is double than B. If pre-exponential factor is same for both reactions then difference in activation energy $E_A - E_B$ is?

A

$-RT \ln 2$

B

$RT \ln 2$

C

$2RT$

D

$\frac{RT}{2}$

Accepted Answer

$-RT \ln 2$

Answer

$RT \ln 2$

Answer

$2RT$

Answer

$\frac{RT}{2}$

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