AIIMS2018Chemistry-Chemical Equilibrium

AIIMS 2018 Chemistry Equilibrium Constant MCQ Question

Type: MCQ-numerical-Medium-Class 11

A+2B2CK=?\text{A} + 2\text{B} \rightleftharpoons 2\text{C} \quad \text{K} = ?

2 mole2\text{ mole} each A\text{A} and B\text{B} present in 10 lt10\text{ lt} so that C\text{C} form is 1 mole1\text{ mole}, Calculate Kc\text{K}_\text{c}

A

1.51.5

B

6.676.67

C

0.150.15

D

2.32.3

Correct Answer

Option B

Detailed Explanation

To calculate the equilibrium constant KcK_c for the reaction A+B2CA + B \rightleftharpoons 2C, we use the equilibrium concentrations: [C]=110mol/L[C] = \frac{1}{10} \, \text{mol/L}, [A]=1.510mol/L[A] = \frac{1.5}{10} \, \text{mol/L}, and [B]=110mol/L[B] = \frac{1}{10} \, \text{mol/L}. The expression for KcK_c is given by Kc=[C]2[A][B]K_c = \frac{[C]^2}{[A][B]}, which, when calculated, yields the correct value corresponding to option B. Other options are incorrect as they do not represent the proper equilibrium constant calculation based on the provided concentrations.

Found an issue with this question?