AIIMS2018Chemistry-Chemical Equilibrium

AIIMS 2018 Chemistry Equilibrium Concentrations MCQ Question

Type: MCQ-numerical-Medium-Class 11

CH3CH=CHCH=NCH3LiAlH4What is final product?\text{CH}_3 - \text{CH} = \text{CH} - \text{CH} = \text{N} - \text{CH}_3 \xrightarrow{\text{LiAlH}_4} \text{What is final product?}

A

CH3CH2CH2CH2NHCH3\text{CH}_3 - \text{CH}_2 - \text{CH}_2 - \text{CH}_2 - \text{NH} - \text{CH}_3

B

CH3CH=CHCH2NHCH3\text{CH}_3 - \text{CH} = \text{CH} - \text{CH}_2 - \text{NH} - \text{CH}_3

C

CH3CH2CH2CH=NCH3\text{CH}_3 - \text{CH}_2 - \text{CH}_2 - \text{CH} = \text{N} - \text{CH}_3

D

CH3CH=CHCH2OH\text{CH}_3 - \text{CH} = \text{CH} - \text{CH}_2 - \text{OH}

Correct Answer

Option B

Detailed Explanation

To find the equilibrium concentration of I₂ (denoted as x), we start with the initial concentration of ICl at 0.6 M. The stoichiometry of the reaction shows that for every 2 moles of ICl that react, 1 mole of I₂ is produced. Thus, at equilibrium, the concentration of I₂ is given by x = (0.6 - 2x)/2. Solving this equation leads to x = 0.256 M, confirming option B as the correct answer. Other options are incorrect because they do not satisfy the stoichiometric relationship or the equilibrium condition derived from the initial concentrations.

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