AIIMS 2016 Chemistry Conductance MCQ Question
A conductivity cell has a cell constant of 0.5 cm⁻¹. This cell when filled with 0.01 M NaCl solution has a resistance of 384 Ω at 25°C. Calculate the equivalent conductance of the given solution.
130.2 Ω⁻¹ cm² (g eq)⁻¹
137.4 Ω⁻¹ cm² (g eq)⁻¹
154.6 Ω⁻¹ cm² (g eq)⁻¹
169.2 Ω⁻¹ cm² (g eq)⁻¹
Correct Answer
Detailed explanation coming soon.
Found an issue with this question?
Related Questions
More from Electrochemistry
Calculate the emf of the cell in which of the following reaction takes place Ni(s) + 2Ag⁺(0.002M) ⟶ Ni²⁺(0.160M) + 2Ag(s) Given that E°cell = 1.05V
The molar conductance of NaCl, HCl and CH₃COONa at infinite dilution are 126.45, 426.16 and 91.0 S cm² mol⁻¹ respectively. The molar conductance of CH...
Given below are half cell reactions: MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O, E° = +1.51 V 1/2 Ω₂ + 2H⁺ + 2e⁻ → H₂O, E° = +1.23 V Will the permanganate ion...