NEET2022Chemistry-Electrochemistry

NEET 2022 Chemistry Electrode Potential MCQ Question

Type: MCQ-conceptual-Medium-Class 12

Given below are half cell reactions:

MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O, E° = +1.51 V

1/2 Ω₂ + 2H⁺ + 2e⁻ → H₂O, E° = +1.23 V

Will the permanganate ion, MnO₄⁻ liberate O₂ from water in the presence of an acid?

A

Yes, because E°cell = +2.733 V

B

No, because E°cell = -2.733 V

C

Yes, because E°cell = +0.287 V

D

No, because E°cell = -0.287 V

Correct Answer

Option D

Detailed Explanation

The permanganate ion will not liberate O₂ from water because the overall cell potential is negative, indicating a non-spontaneous reaction.

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