AIIMS2019Chemistry-Chemical Bonding
AIIMS 2019 Chemistry Hybridization MCQ Question
Type: MCQ-conceptual-Medium-Class 11
PCl₅, BrF₅, IF₇
A
sp³d
B
sp³d²
C
sp³d³
D
sp³d⁴
Correct Answer
Option C
Detailed Explanation
The molecular geometry of PCl₅, BrF₅, and IF₇ involves the use of d-orbitals in their bonding, which corresponds to an sp³d³ hybridization. In these compounds, the central atom uses five d-orbitals to accommodate the bonding pairs and lone pairs, leading to a trigonal bipyramidal (PCl₅) or octahedral (BrF₅ and IF₇) geometry. Options A (sp³d), B (sp³d²), and D (sp³d⁴) are incorrect as they do not account for the presence of seven total electron pairs, which is necessary for the correct hybridization in these molecules.
Found an issue with this question?