AIIMS 2018 Chemistry Hybridization MCQ Question

In N₂H₂ (hydrazine), the nitrogen atoms are bonded to each other and to hydrogen, allowing for greater s-character in the N–H bonds due to the sp² hybridization of nitrogen, which involves one s orbital and two p orbitals. This results in a higher percentage of s-character compared to the other options. In contrast, N₂H₄ (hydrazine) has sp³ hybridized nitrogen, NH₃ (ammonia) also has sp³ hybridization, and NH₄⁺ (ammonium) exhibits sp³ hybridization as well, all resulting in lower s-character in their N–H bonds.