STANDARDZoology-Genetics
STANDARD Zoology Hardy-Weinberg Principle MCQ Question
Type: MCQ-numerical-Medium
A gene locus has two alleles A, a. If the dominant allele A is 0.4, then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population
A
0.16(M) ; 0.48(Aa) ; 0.36(aa)
B
0.36(M) ; 0.48(Aa) ; 0.16(aa)
C
0.36(M) ; 0.24(Aa) ; 0.36(aa)
D
0.16(M) ; 0.24(Aa) ; 0.36(aa)
Correct Answer
Option A
Detailed Explanation
Frequency of dominant allele p = 0.4. Applying Hardy Weinberg equilibrium: p + q = 1 ⇒ q = 1 − 0.4 = 0.6. p² + q² + 2pq = 1. Frequency of homozygous dominant genotype: (p²/AA) = (0.4)² = 0.16. Frequency of Heterozygote (2pq/Aa) = 2 × 0.4 × 0.6 = 0.48. Frequency of homozygous recessive genotype: (q²/aa) = (0.6)² = 0.36.
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