STANDARD Physics Interference MCQ Question
Two slits in Young's double slit experiment have widths in the ratio 81 : 1. The ratio of the amplitudes of light waves is
3 : 1
3 : 2
9 : 1
6 : 1
Correct Answer
Detailed Explanation
The amplitude ratio is proportional to the square root of the intensity ratio. Given the width ratio β₁/β₂ = 81/1, the amplitude ratio A₁/A₂ = √(I₁/I₂) = √(81/1) = 9/1.
Found an issue with this question?
Related Questions
More from Wave Optics
More from
In a Young's double-slit experiment, the distance between the slits is 0.025 mm, the screen is placed 5 cm away, and the wavelength of light used is 5...
Match Column-I with Column-II. Column-I Column-II (a) Coherent sources (i) Produce interference patterns (b) Incoherent sources (ii) Intensi...
Consider a diagram where spheres of radius vt are drawn from each point on a spherical wavefront, and a common tangent is drawn to all these spheres. ...