STANDARD Physics Diffraction MCQ Question
A screen is placed 50 cm from a single slit which is illuminated with light of wavelength 6000 Å. If the distance between the first and third minima in the diffraction pattern is 3.0 mm. The width of the slit is
1 × 10⁻⁴ m
2 × 10⁻⁴ m
0.5 × 10⁻⁴ m
4 × 10⁻⁴ m
Correct Answer
Detailed Explanation
The position of nth minima in the diffraction pattern is xₙ = nDλ/d. Solving for d using the given values, d = 2 × 10⁻⁴ m.
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