STANDARD Physics Refraction MCQ Question
Three immiscible liquids of densities d₁ > d₂ > d₃ and refractive indices μ₁ > μ₂ > μ₃ are put in a beaker. The height of each liquid column is h/3. A dot is made at the bottom of the beaker. For near normal vision, the apparent depth of the dot is
h/6 (1/μ₁ + 1/μ₂ + 1/μ₃)
h/6 (1/μ₁ - 1/μ₂ - 1/μ₃)
h/3 (1/μ₁ - 1/μ₂ - 1/μ₃)
h/3 (1/μ₁ + 1/μ₂ + 1/μ₃)
Correct Answer
Detailed Explanation
The apparent depth is calculated by summing the contributions of each layer's refractive index. The formula used is h/3 (1/μ₁ + 1/μ₂ + 1/μ₃), which accounts for the refractive indices of all three layers.
Found an issue with this question?
Related Questions
More from
Assertion (A): The thin lens formula is applicable to both convex and concave lenses for real and virtual images. | Reason (R): The focal points of a ...
Consider a diagram where a parallel beam of light is incident on a concave mirror. The reflected rays converge at a point on the principal axis. What ...
Match Column-I with Column-II. Column-I Column-II (a) Simple Microscope (i) Used for terrestrial observations (b) Refracting Telescope (...