STANDARD Physics Combination of Resistors MCQ Question
Two resistors of resistances R₁ = (100 ± 3)Ω and R₂ = (200 ± 4)Ω are connected in parallel. The equivalent resistance of the parallel combination is
(66.7 ± 1.8)Ω
(66.7 ± 4.0)Ω
(66.7 ± 3.0)Ω
(66.7 ± 7.0)Ω
Correct Answer
Detailed Explanation
The equivalent resistance in parallel combination is 1/Rₚ = 1/R₁ + 1/R₂ = 1/100 + 1/200 = 3/200. Therefore, Rₚ = 200/3 = 66.7Ω. The error in equivalent resistance is given by ΔRₚ = ΔR₁(Rₚ/R₁)² + ΔR₂(Rₚ/R₂)² = 1.8Ω.
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