STANDARD Physics Combination of Resistors MCQ Question
Three resistors of resistances 3 Ω, 4 Ω and 5 Ω are combined in parallel. This combination is connected to a battery of emf 12 V and negligible internal resistance, current through each resistor in ampere is
4, 3, 2.4
8, 7, 3.4
2, 5, 1.8
5, 5, 8.2
Correct Answer
Detailed Explanation
Since the voltage across the circuit is constant, the current through each resistor can be calculated using Ohm's law: I = V/R. For the 3 Ω resistor, I₁ = 12/3 = 4 A. For the 4 Ω resistor, I₂ = 12/4 = 3 A. For the 5 Ω resistor, I₃ = 12/5 = 2.4 A.
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