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STANDARDPhysics-Alternating Current

STANDARD Physics Power Factor MCQ Question

Type: MCQ-numerical-Medium-Class 12

A resistor of 500 Ω and an inductance of 0.5 H are in series with an ac source which is given by V = 100√2 sin(1000t). The power factor of the combination is

A

1/√2

B

1/√3

C

0.5

D

0.6

Correct Answer

Option A

Detailed Explanation

The impedance Z is calculated using Z = √(R² + (X_L - X_C)²). Here, X_L = ωL = 1000 × 0.5 = 500 Ω. The power factor is cos(ϕ) = R/Z = 500/500√2 = 1/√2.

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