STANDARD Physics Work-Energy Theorem MCQ Question
A block of mass 10 kg is moving in x-direction with a constant speed of 10 m s⁻¹. It is subjected to a retarding force Fᵣ = -0.1 x J m⁻¹ during its travel from x = 20 m to x = 30 m. Its final kinetic energy will be
250 J
275 J
450 J
475 J
Correct Answer
Detailed Explanation
From work-energy theorem, the work done is equal to the change in kinetic energy. The work done by the retarding force is calculated as the integral of Fᵣ over the distance, resulting in a change in kinetic energy. The final kinetic energy is 475 J.
Found an issue with this question?
Related Questions
More from Work, Energy and Power
A body of mass 1 kg begins to move under the action of a time dependent force F = (2t î + 3t² ĵ)N, where î and ĵ are unit vectors along x and y ax...
A particle acted upon by constant forces 4î + ĵ − 3k̂ and 3î + ĵ − k̂ is displaced from the point î + 2ĵ + k̂ to point 5î + 4ĵ + k̂. The total...
More from
Which of the following statements about power is correct?
Assertion (A): The work-energy theorem is an integral form of Newton's second law. | Reason (R): The work-energy theorem involves an integral over an ...
Assertion (A): The dot product of two vectors is zero when the vectors are perpendicular. | Reason (R): The scalar product of two vectors is the produ...