STANDARD Physics Work Done by a Constant Force MCQ Question
In the previous question, the work done by friction in 10 s is
200 J
−200 J
600 J
−600 J
Correct Answer
Detailed Explanation
The frictional force and the displacement are in opposite direction, therefore the angle between frictional force and displacement is θ = 180°. Thus, work done by the friction is W₁ = f d cos 180° = (2 N)(100 m) cos 180° = −200 J.
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