STANDARD Physics Wave Speed on a String MCQ Question
A string of mass 2.5 kg is under a tension of 200 N. The length of the stretched string is 20 m. If the transverse jerk is struck at one end of the string, the disturbance will reach the other end in
one second
0.5 second
2 second
data given is insufficient.
Correct Answer
Detailed Explanation
The speed of the wave on the string is given by v = √(T/μ), where μ is the mass per unit length. Here, μ = 2.5 kg / 20 m = 0.125 kg/m. Therefore, v = √(200/0.125) = 40 m/s. Time taken = length/speed = 20/40 = 0.5 seconds.
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