STANDARD Physics Longitudinal Vibrations MCQ Question
A granite rod of 60 cm length is clamped at its middle point and is set into longitudinal vibrations. The density of granite is 2.7 × 10³ kg m⁻³ and its Young's modulus is 9.27 × 10¹⁰ Pa. What will be the fundamental frequency of the longitudinal vibrations?
5 kHz
2.5 kHz
10 kHz
7.5 kHz
Correct Answer
Detailed Explanation
The fundamental frequency f is given by f = (1/2L)√(Y/ρ), where L is the length, Y is Young's modulus, and ρ is density. Substituting the given values, f = (1/1.2)√(9.27 × 10¹⁰ / 2.7 × 10³) ≈ 5 kHz.
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