STANDARD Physics Young's Double Slit Experiment MCQ Question
In Young's double slit experiment the distance d between the slits S₁ and S₂ is 1 mm. What should the width of each slit be, so as to obtain 10th maxima of the double slit pattern within the central maximum of the single slit pattern?
0.9 mm
0.8 mm
0.2 mm
0.6 mm
Correct Answer
Detailed Explanation
The angular separation between n bright fringes, θₙ = nλ/d. For 10 bright fringes, θ₁₀ = 10λ/d. The angular width of the central maximum in the diffraction pattern due to slit of width a is 2λ/a. Now 10λ/d ≤ 2λ/a or a ≤ d/5 = 1/5 mm = 0.2 mm.
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