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STANDARDPhysics-Wave Optics

STANDARD Physics Young's Double Slit Experiment MCQ Question

Type: MCQ-numerical-Medium-Class 12

In a double slit experiment using light of wavelength 600 nm, the angular width of a fringe on a distant screen is 0.1°. The spacing between the two slits is

A

3.44 × 10⁻⁴ m

B

1.54 × 10⁻⁴ m

C

1.54 × 10⁻³ m

D

1.44 × 10⁻³ m

Correct Answer

Option A

Detailed Explanation

The angular width of the fringe is given by θ = λ/d. Rearranging gives d = λ/θ. Substituting the given values, d = (600 × 10⁻⁹ m) / (3.14/1800) = 3.44 × 10⁻⁴ m.

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