STANDARD Physics Young's Double Slit Experiment MCQ Question
In Young's double slit experiment the ratio intensity of the maxima and minima in the inference experiment is 25 : 9. The ratio of widths of two slits is
18 : 3
4 : 1
8 : 1
16 : 1
Correct Answer
Detailed Explanation
The intensity ratio is given by (A₁ + A₂)²/(A₁ - A₂)² = 25/9. Solving for A₁/A₂ gives A₁/A₂ = 4, which means the width ratio is 16:1.
Found an issue with this question?
Related Questions
More from Wave Optics
More from
In a Young's double-slit experiment, the distance between the slits is 0.025 mm, the screen is placed 5 cm away, and the wavelength of light used is 5...
Match Column-I with Column-II. Column-I Column-II (a) Coherent sources (i) Produce interference patterns (b) Incoherent sources (ii) Intensi...
Consider a diagram where spheres of radius vt are drawn from each point on a spherical wavefront, and a common tangent is drawn to all these spheres. ...