STANDARD Physics Young's Double Slit Experiment MCQ Question
In Young's double slit experiment distance between two sources is 0.1 mm. The distance of screen from the source is 20 cm. Wavelength of light used is 5460 Å. Then, angular position of the first dark fringe is
0.08°
0.16°
0.20°
0.31°
Correct Answer
Detailed Explanation
The angular position of the first dark fringe is given by θ₁ = (2n - 1) λ/2d. For the first dark fringe, n = 1. Substituting the given values, θ₁ = (5460 × 10⁻¹⁰ m) / (2 × 0.1 × 10⁻³ m) = 0.16°.
Found an issue with this question?
Related Questions
More from Wave Optics
More from
In a Young's double-slit experiment, the distance between the slits is 0.025 mm, the screen is placed 5 cm away, and the wavelength of light used is 5...
Match Column-I with Column-II. Column-I Column-II (a) Coherent sources (i) Produce interference patterns (b) Incoherent sources (ii) Intensi...
Consider a diagram where spheres of radius vt are drawn from each point on a spherical wavefront, and a common tangent is drawn to all these spheres. ...