STANDARD Physics Double Slit Interference MCQ Question
The two slits are 1 mm apart from each other and illuminated with a light of wavelength 5 × 10⁻⁷ m. If the distance of the screen is 1 m from the slits, then the distance between third dark fringe and fifth bright fringe is
1.2 mm
0.75 mm
1.25 mm
0.625 mm
Correct Answer
Detailed Explanation
The distance between the third dark fringe and the fifth bright fringe is calculated using the formula for fringe separation. For the third dark fringe, n = 3, and for the fifth bright fringe, n = 5. Using the formula, the distance is found to be 1.25 mm.
Found an issue with this question?
Related Questions
More from Wave Optics
More from
In a Young's double-slit experiment, the distance between the slits is 0.025 mm, the screen is placed 5 cm away, and the wavelength of light used is 5...
Match Column-I with Column-II. Column-I Column-II (a) Coherent sources (i) Produce interference patterns (b) Incoherent sources (ii) Intensi...
Consider a diagram where spheres of radius vt are drawn from each point on a spherical wavefront, and a common tangent is drawn to all these spheres. ...