STANDARD Physics Isothermal Processes MCQ Question
1 mole of gas expands isothermally at 37°C. The amount of heat is absorbed by it until its volume doubled is (R = 8.31 J mol⁻¹ K⁻¹)
411.25 cal
418.50 cal
420.25 cal
425.40 cal
Correct Answer
Detailed Explanation
In an isothermal process, the work done is given by W = nRT ln(V₂/V₁). Here, T = 310 K and V₂ = 2V₁. Substituting the values, W = 8.31 × 310 × ln 2 = 1.786 × 10³ J. Converting to calories, the heat absorbed is approximately 425.4 cal.
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