STANDARD Physics Heat Transfer MCQ Question
A heat source at T = 10³ K is connected to another heat reservoir at T = 10² K by a copper slab which is 1 m thick. Given that the thermal conductivity of copper is 0.1 W K⁻¹ m⁻¹, the energy flux through it in the steady state is
120 W m⁻²
90 W m⁻²
200 W m⁻²
65 W m⁻²
Correct Answer
Detailed Explanation
The energy flux is given by , where k is the thermal conductivity, T₁ and T₂ are the temperatures, and d is the thickness. Substituting the given values, W m⁻².
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