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STANDARD Physics Heat Capacity MCQ Question

Type: MCQ-numerical-Medium-Class 11

The amount of heat supplied to 4×10−24 \times 10^{-2} kg of nitrogen at room temperature to rise its temperature by 50°C at constant pressure is (Molecular mass of nitrogen is 28 and R=8.3 J mol−1 K−1R = 8.3 \text{ J mol}^{-1} \text{ K}^{-1})

A

2.08 kJ

B

3.08 kJ

C

4.08 kJ

D

5.08 kJ

Correct Answer

Option A

Detailed Explanation

Using the formula Q=nCpΔTQ = nC_p \Delta T, where n=mMn = \frac{m}{M}, Cp=7R2C_p = \frac{7R}{2}, and ΔT=50°C\Delta T = 50 \text{°C}, we find Q=2.08 kJQ = 2.08 \text{ kJ}.

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