STANDARDPhysics-Chemical Thermodynamics
STANDARD Physics Gibbs Free Energy MCQ Question
Type: MCQ-numerical-Medium-Class 11
For a reversible reaction at 298 K the equilibrium constant K is 200. What is the value of ΔG° at 298 K?
A
−13.13 kcal
B
−0.13 kcal
C
−3.158 kcal
D
−0.413 kcal
Correct Answer
Option C
Detailed Explanation
Using the formula ΔG° = −2.303 RT × log K, where R = 2 cal/mol·K and T = 298 K, we calculate ΔG° = −2.303 × 2 × 298 × log 200 = −3.158 kcal.
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