STANDARD Physics Carnot Engine MCQ Question
An engine has an efficiency of 0.25. When temperature of sink is reduced by 58°C, if its efficiency is doubled, then the temperature of the source is
150°C
222°C
242°C
232°C
Correct Answer
Detailed Explanation
The efficiency of an engine is given by η = 1 - T₂/T₁. Initially, η₁ = 0.25, so T₂/T₁ = 0.75. When the efficiency is doubled, η₂ = 0.5, so T₂/T₁ = 0.5. Solving these equations with the given temperature change, we find T₁ = 232°C.
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