STANDARDPhysics-Thermodynamics

STANDARD Physics Adiabatic Processes MCQ Question

Type: MCQ-numerical-Medium-Class 11

A monatomic gas is compressed adiabatically to 14\frac{1}{4} of its original volume, the final pressure of gas in terms of initial pressure P is

A

7.08 P

B

8.08 P

C

9.08 P

D

10.08 P

Correct Answer

Option D

Detailed Explanation

The initial pressure and volume of gas are P and V. Now the gas is compressed adiabatically to 1/4th of its original volume. Using the relation P1V1γ=P2V2γP_1 V_1^\gamma = P_2 V_2^\gamma and γ=53\gamma = \frac{5}{3} for monatomic gases, we find P2=10.08PP_2 = 10.08 P.

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