STANDARDPhysics-Thermodynamics
STANDARD Physics Adiabatic Processes MCQ Question
Type: MCQ-numerical-Medium-Class 11
Two moles of an ideal monoatomic gas occupy a volume 2V at temperature 300 K, it expands to a volume 4V adiabatically, then the final temperature of gas is
A
179 K
B
189 K
C
199 K
D
219 K
Correct Answer
Option B
Detailed Explanation
In an adiabatic process, T₂V₂^(γ-1) = T₁V₁^(γ-1). Substituting V₁ = 2V, V₂ = 4V, T₁ = 300 K, and γ = 5/3 for a monoatomic gas, we find T₂ ≈ 189 K.
Found an issue with this question?
Related Questions
More from Thermodynamics
A Carnot engine has an efficiency of 50% when its source is at a temperature 327° C. The temperature of the sink is :
2023Physics
A system goes from A to B by two different paths in the P-V diagram as shown in figure. Heat given to the system in path 1 is 1100 J, the work done by...
Physics
Among the following, the set of parameters that represents path function is: (A) q + w (B) q (C) w (D) H − TS
Chemistry