STANDARDPhysics-Thermodynamics
STANDARD Physics Adiabatic Processes MCQ Question
Type: MCQ-numerical-Medium-Class 11
Two moles of an ideal monoatomic gas occupy a volume 2V at temperature 300 K, it expands to a volume 4V adiabatically, then the final temperature of gas is
A
179 K
B
189 K
C
199 K
D
219 K
Correct Answer
Option B
Detailed Explanation
In an adiabatic process, T₂V₂^(γ-1) = T₁V₁^(γ-1). Substituting V₁ = 2V, V₂ = 4V, T₁ = 300 K, and γ = 5/3 for a monoatomic gas, we find T₂ ≈ 189 K.
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