STANDARDPhysics-Thermal Properties of Matter
STANDARD Physics Thermal Conductivity MCQ Question
Type: MCQ-numerical-Medium-Class 11
A wall is made of equally thick layers A and B of different materials. Thermal conductivity of A is twice that of B. In the steady state, the temperature difference across the wall is 36°C. The temperature difference across the layer A is
A
12°C
B
18°C
C
6°C
D
24°C
Correct Answer
Option A
Detailed Explanation
The temperature difference across layer A can be calculated using the formula for thermal conductivity. Since Kₐ = 2K_b and Tₐ - T_b = 36°C, solving the equations gives Tₐ - T = 12°C.
Found an issue with this question?