STANDARD Physics Thermal Conductivity MCQ Question
A wall is made of equally thick layers A and B of different materials. Thermal conductivity of A is twice that of B. In the steady state, the temperature difference across the wall is 36°C. The temperature difference across the layer A is
12°C
18°C
6°C
24°C
Correct Answer
Detailed Explanation
The temperature difference across layer A can be calculated using the formula for thermal conductivity. Since Kₐ = 2K_b and Tₐ - T_b = 36°C, solving the equations gives Tₐ - T = 12°C.
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