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STANDARDPhysics-Atomic Structure

STANDARD Physics Quantum Numbers MCQ Question

Type: MCQ-conceptual-Medium-Class 11

The orbital angular momentum for an electron revolving in an orbit is given by l(l+1)h2π\sqrt{l(l+1)} \frac{h}{2\pi}. This momentum for an s-electron will be given by

A

Zero

B

h2π\frac{h}{2\pi}

C

2⋅h2π\sqrt{2} \cdot \frac{h}{2\pi}

D

12⋅h2π\frac{1}{2} \cdot \frac{h}{2\pi}

Correct Answer

Option A

Detailed Explanation

For s-electron, l = 0. Orbital angular momentum = 0(0+1)h2π=0\sqrt{0(0+1)} \frac{h}{2\pi} = 0.

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