STANDARDPhysics-Atomic Structure
STANDARD Physics Bohr's Model MCQ Question
Type: MCQ-conceptual-Medium-Class 11
A triply ionized beryllium Be³⁺ has the same orbital radius as the ground state of hydrogen. Then the quantum state n of Be³⁺ is
A
n = 1
B
n = 2
C
n = 3
D
n = 4
Correct Answer
Option B
Detailed Explanation
The radius of the nth orbit in hydrogen-like atoms is given by rₙ = a₀n²/Z. For hydrogen, Z = 1, and for Be³⁺, Z = 4. Equating the radii, we find n = 2 for Be³⁺ to have the same radius as the ground state of hydrogen.
Found an issue with this question?