STANDARD Physics Bohr Model MCQ Question
The de-Broglie wavelength of an electron in the first Bohr orbit is
equal to one-fourth the circumference of the first orbit
equal to half the circumference of first orbit
equal to twice the circumference of first orbit
equal to the circumference of the first orbit.
Correct Answer
Detailed Explanation
In the first Bohr orbit, the angular momentum is quantized as nh/2π. The de-Broglie wavelength λ is given by h/p, where p is the momentum. For the first orbit, n = 1, and the circumference is 2πr₁. Thus, λ = 2πr₁, which is the circumference of the first orbit.
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