STANDARD Physics Velocity and Acceleration in SHM MCQ Question

In simple harmonic motion (SHM), the velocity $v$ is maximum when the particle is at the equilibrium position, while the acceleration $a$ is maximum at the extreme positions where the displacement from equilibrium is greatest. Therefore, option C is correct because when $v$ is at its maximum, $a$ is at its maximum as well, reflecting the relationship $a = -\omega^2 x$, where $x$ is the displacement.

Option A is incorrect because when $v$ is maximum, $a$ is not zero; it is maximum at that point. Option B is false since when $v$ is zero (at the extremes), $a$ is maximum, not zero. Option D is misleading because $a$ cannot be zero while $v$ is non-zero in SHM; they are inversely related at different points in the motion.