STANDARDPhysics-Rotational Motion
STANDARD Physics Torque MCQ Question
Type: MCQ-numerical-Medium
The moment of the force, F = 4î + 5ĵ - 6k̂ at (2, 0, -3), about the point (2, -2, -2), is given by
A
-8î - 4ĵ - 7k̂
B
-4î - ĵ - 8k̂
C
-7î - 8ĵ - 4k̂
D
-7î - 4ĵ - 8k̂
Correct Answer
Option D
Detailed Explanation
The moment of the force is calculated using τ = (r - r₀) × F. By substituting the given values and performing the cross product, the result is -7î - 4ĵ - 8k̂.
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