STANDARD Physics Moment of Inertia MCQ Question
A hollow cylinder of mass M and radius R is rotating about its axis of symmetry and a solid sphere of same mass and radius is rotating about an axis passing through its centre. If torques of equal magnitude are applied to them, then the ratio of angular accelerations produced is
2/5
5/2
5/4
4/5
Correct Answer
Detailed Explanation
Moment of inertia of hollow cylinder about its axis of symmetry, I₁ = MR². Moment of inertia of solid sphere about an axis passing its centre, I₂ = 2/5 MR². Let α₁ and α₂ be angular accelerations produced in the cylinder and the sphere respectively on applying same torque τ in each case. Then α₁ = τ/I₁ and α₂ = τ/I₂. Their corresponding ratio is α₁/α₂ = I₂/I₁ = 5MR²/2MR² = 2/5.
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