STANDARD Physics Angular Position and Torque MCQ Question
The instantaneous angular position of a point on rotating wheel is given by the equation θ(t) = 2t³ – 6t². The torque on the wheel becomes zero at
t = 1 s
t = 0.5 s
t = 0.25 s
t = 2 s
Correct Answer
Detailed Explanation
The angular acceleration α is the second derivative of θ(t), which is 12t - 12. Setting α = 0 gives 12t - 12 = 0, so t = 1 s.
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