STANDARD Physics Shear Modulus MCQ Question
The metal cube of side 10 cm is subjected to a shearing stress of 10⁴ N m⁻². The modulus of rigidity if the top of the cube is displaced by 0.05 cm with respect to its bottom is
2 × 10⁶ N m⁻²
10⁵ N m⁻²
1 × 10⁷ N m⁻²
4 × 10⁵ N m⁻²
Correct Answer
Detailed Explanation
The modulus of rigidity η is calculated using η = Shearing stress / Shearing strain. The shearing strain is Δl / l = 0.05 / 10 = 0.005. Therefore, η = 10⁴ / 0.005 = 2 × 10⁶ N m⁻².
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