STANDARD Physics Range of Projectile MCQ Question
Galileo writes that for angles of projection of a projectile at angles (45° + θ) and (45° − θ), the horizontal ranges described by the projectile are in the ratio of (if θ ≤ 45°)
2 : 1
1 : 2
1 : 1
2 : 3
Correct Answer
Detailed Explanation
For a projectile launched with velocity u at an angle θ, the horizontal range is given by R = (u² sin 2θ) / g. For θ₁ = 45° − θ and θ₂ = 45° + θ, the ranges R₁ and R₂ are equal, hence the ratio is 1:1.
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