STANDARDPhysics-Projectile Motion
STANDARD Physics Range of Projectile MCQ Question
Type: MCQ-conceptual-Medium
The horizontal range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will be
A
60 m
B
71 m
C
100 m
D
141 m
Correct Answer
Option C
Detailed Explanation
The horizontal range R is given by R = (u² sin 2θ) / g. For the same speed, R ∝ sin 2θ. Therefore, R₁/R₂ = sin 2×15° / sin 2×45°. Solving gives R₂ = 50 m × (1/0.5) = 100 m.
Found an issue with this question?