STANDARD Physics Range of Projectile MCQ Question
The horizontal range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will be
60 m
71 m
100 m
141 m
Correct Answer
Detailed Explanation
The horizontal range R is given by R = (u² sin 2θ) / g. For the same speed, R ∝ sin 2θ. Therefore, R₁/R₂ = sin 2×15° / sin 2×45°. Solving gives R₂ = 50 m × (1/0.5) = 100 m.
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