STANDARDPhysics-Projectile Motion
STANDARD Physics Maximum Height MCQ Question
Type: MCQ-conceptual-Medium
Two balls are projected at an angle θ and (90° − θ) to the horizontal with the same speed. The ratio of their maximum vertical heights is
A
1 : 1
B
tanθ : 1
C
1 : tanθ
D
tan²θ : 1
Correct Answer
Option D
Detailed Explanation
The maximum height for a projectile is given by H = (u²sin²θ)/(2g). For angles θ and (90° − θ), the heights are H₁ = (u²sin²θ)/(2g) and H₂ = (u²cos²θ)/(2g). Dividing H₁ by H₂ gives tan²θ : 1.
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