STANDARD Physics Angle of Projection MCQ Question
If R and H represent horizontal range and maximum height of the projectile, then the angle of projection with the horizontal is
tan⁻¹(H/R)
tan⁻¹(2H/R)
tan⁻¹(4H/R)
tan⁻¹(4R/H)
Correct Answer
Detailed Explanation
The maximum height H is given by (u²sin²θ)/(2g) and the range R by (u²sin2θ)/g. Dividing H by R and simplifying gives tanθ = 4H/R, so θ = tan⁻¹(4H/R).
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