STANDARD Physics Simple Harmonic Motion MCQ Question
A rectangular block of mass m and area of cross-section floats in a liquid of density ρ. If is given a small vertical displacement from equilibrium it undergoes oscillation with a time period T. Then
T ∝ 1/√m
T ∝ √ρ
T ∝ 1/√A
T ∝ 1/ρ
Correct Answer
Detailed Explanation
The time period T of oscillation for a floating block is derived from the formula T = 2π√(m/Aρg), which simplifies to T ∝ 1/√A. This indicates that the time period is inversely proportional to the square root of the area of cross-section.
Found an issue with this question?
Related Questions
More from
Assertion (A): The acceleration in simple harmonic motion is always directed towards the mean position. | Reason (R): In simple harmonic motion, accel...
What is the relationship between the driving frequency and the amplitude of an oscillator in Simple Harmonic Motion?
What happens to the mechanical energy of a damped oscillator during its motion?