STANDARD Physics Simple Harmonic Motion MCQ Question
The frequency of oscillations of a mass m suspended by a spring is v₁. If the length of the spring is cut to one-half, the same mass oscillates with frequency v₂. The value v₂/v₁ is
2
√2
4
√3
Correct Answer
Detailed Explanation
The frequency of oscillations of mass m and force constant k is v₁ = (1/2π)√(k/m). When the spring is cut to one-half of its length, its force constant is doubled (2k). Then frequency of oscillation of mass m will be v₂ = (1/2π)√(2k/m). Therefore, v₂/v₁ = √2.
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