STANDARD Physics Simple Harmonic Motion MCQ Question

In simple harmonic motion (SHM), the acceleration of the particle is maximum at the extreme positions of the displacement, which occurs at $t = \frac{T}{4}$ and $t = \frac{3}{4}T$. At $t = \frac{3}{4}T$, the particle is at its maximum displacement in the opposite direction, resulting in maximum acceleration. Conversely, the velocity is maximum at $t = \frac{T}{2}$ when the particle passes through the equilibrium position, making options A and B incorrect. Option C is also incorrect because the maximum acceleration occurs at the extreme positions, not at $t = \frac{T}{4}$.